第九章测试
1.The first step in testing a hypothesis is to establish _______.
A:a power function B:a not rejectance hypothesis and a rejection hypothesis C:a null hypothesis and alternative hypothesis D:an indirect hypothesis
答案:C
2.Consider the following null and alternative hypotheses.Ho:  m  <=7Ha:  m > 6These hypotheses _______________.
A:are established correctly B:are not mutually exclusive C:do not reference a population parameter D:are not collectively exhaustive 3.Consider the following null and alternative hypotheses.Ho: m >= 7Ha: m < 6These hypotheses _______________.
A:are established correctly B:are not mutually exclusive C:do not reference a population parameter D:are not collectively exhaustive 4.Consider the following null and alternative hypotheses.Ho:  图片11.png£ 352Ha: 图片11.png > 352These hypotheses _______________.
A:are not collectively exhaustive B:are not mutually exclusive C:do not reference a population parameter D:are established correctly 5.The region of the distribution in hypothesis testing in which the null hypothesis is rejected is called the _______.
A:not rejectance region B:rejection region C:alternative region D:null region 6.The rejection and not rejectance regions are divided by a point called the _______.
A:not rejectance value B:critical value C:rejection value D:dividing point 7.The probability of committing a Type II error is represented by _______.
A:1 – a B:a C:a / 2 D:b 8.Jennifer Cantu, Customer Services Manager at Tri-Nation Auto Insurance, monitors the claims processing time of the claims division. Her standard includes ‘a mean processing time of 5 days or less’. Each week, her staff checks for compliance by analysing a random sample of 60 claims. Jennifer’s alternative hypothesis is ________.
A:> 5 B:5 C:n = 60 D:< 5 9.The manufacturers of a deodorant claim that the mean drying time of their product is, at most, 15 minutes. A sample consisting of 16 cans of the product was used to test the manufacturer’s claim. The experiment yielded a mean drying time of 18 minutes with a standard deviation of 6 minutes. Test the claim at the 0.05 significance level.
A:Computed test statistic = 2 and is greater than 1.96, so reject H0: µ ≤ 15. B:Computed test statistic = 2 and is greater than 1.645, so reject H0: µ ≤ 15. C:Computed test statistic = 2 and is greater than 2.131, so reject H0: µ ≤ 15. D:Computed test statistic = 2 and is greater than 1.753, so reject H0: µ = 15. 10.What happens to the rejection region if the level of significance is changed from 0.10 to 0.05?
A:it gets larger B:it does not change C:it gets smaller

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