第三章单元测试
Fossilised biomass has been exploited as coal and oil.
The relative distribution of phenolic nuclei in lignin strongly differs between plant species.
The role of hemicellulose is to modify and crosslink the basic fibrils and promote the interaction between other biopolymers.
Softwoods are mainly vessel members, fibres, and parenchyma, and hardwoods are mainly made of made of tracheids and parenchyma.
The outer layer (S1) is thicker than The middle layer (S2).
Klason lignin is a standard analytical method to measure the lignin content of lignocellulosic biomass.
For esterification reaction of cellulose, the conversion was low and for silynation reaction, the conversion is good but with a high cost.
Cellulose has many hydroxyl groups which can form hydrogen bonding linked network easily.
Highly porous aerogels usually tend to show higher oil-sorption capacities
Starch only has one forms, i.e. amylose.
In addition to glucomannan, minor amounts of miscellaneous polysaccharides are present in hardwoods.
The softening temperature (Ts) of lignins in dry state is higher than that in moist lignins.
The reactivity of lignin has nothing to do with its solubility.
Lignin mainly has two types of linkages including C-C and C-O-C.
The non-bonded orbital interactions (π-π interactions) of the aromatic groups could caused the association of lignin molecules.
The aromatic moieties present in the lignin structure will improve the mechanical and thermal properties of epoxy resins.
There are two different types of polysaccharide hydrolysis, involving acidic (sulfuric acid) or enzymatic reactions.
Terpene is derive from a 5C compound, isoprene.
Polyphenols also characteristically possess a significant binding affinity for proteins, which can lead to the formation of soluble and insoluble protein-polyphenol complexes
Cardanol double bond may be epoxidised or undergo olefin-metathesis reaction which may act as modified monomer for the formation of different set of polymers.
A:错 B:对
答案:对
A:错 B:对
A:错 B:对
A:错 B:对
A:错 B:对
A:错 B:对
A:对 B:错
A:错 B:对
A:错 B:对
A:错 B:对
A:错 B:对
A:错 B:对
A:对 B:错
A:对 B:错
A:对 B:错
A:对 B:错
A:对 B:错
A:对 B:错
A:错 B:对
A:错 B:对
