第五章单元测试
- Secondary consumers in the activated sludge system include: ( ).
- Which one of the following is the most popular reactor configurations being used in wastewater treatment these days ( ).
- The conventional activated sludge system could remove BOD5 and suspended solids (SS) by ( ) percent or more for municipal sewage treatment.
- For a conventional design for the activated sludge treatment of domestic sewage, the F/M ratio suggested is 0.25 to 0.5 kg BOD5 per day per kg MLSS.（ ）
- In most situations, the electron donor, or the BOD, is rate limiting for microorganism reproduction and growth.（ ）
A:predators
B:prokaryotes
C:heterotrophic bacteria
D:chemolithotrophic bacteria
答案:predators
###prokaryotes
###chemolithotrophic bacteria
A:Completely mixed
B:Conventional Aeration
C:Step aeration
D:Modified Aeration
A:80
B:75
C:85
D:90
A:错 B:对
A:对 B:错
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